# How To Solve Any Projectile Motion Problem (The Toolbox Method)

Introducing the “Toolbox” method of solving projectile motion problems! Here we use kinematic equations and modify with initial conditions to generate a “toolbox” of equations with which to solve a classic three-part projectile motion problem.

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**Video Rating: / 5**

Really helpful video thank you

The systematic and beautiful way of solving a problem.

Thank you!!^_^Wait. Couldn't you have used the trajectory formula for at least the range and peak height?

This is a great video Jesse! I'm taking my first physics class ever at a community college and your toolbox method really solidified what I've been learning in school. Thanks!

What are the conditions if tank is moving in horizontal direction and never stops

You are the awsome one.I like your way of teaching.

Why is it plus g instead of minus g

Fucken oaf imma drop out physics.

Freakin amazing.

ISNT THE VERTICAL DISPLACEMENT UPON IMPACT 100

This was amazing

I was trying to use my calculator for the QUAD formula on the time variable and I'm not getting even close to the same answer you did… not sure what I could be doing incorrect, I've retyped it 1000 times.

Thanks very much it’s been super helpful

Learned more in 13 min than 4 weeks so far

why yellow ?

Can someone answer, where did he get that 5.68 seconds in finding the range?

How do you get 5.68 seconds and -3.59 seconds?

Can you please clarify on the quadratic equation part?

I solved it myself and got results:

X sub 1= 3.344

X sub 2= -5.4359

I think i got something wrong? Haha i use a fx-991ES calculator

The equation is:

[[-(1/2)(9.81)]√[(30)(sin20)]² – 4[(1/2)(9.81)](100)]/2(1/2)(9.81)

am i wrong?